54m^2-16=0

Solution for 54m^2-16=0 equation:

54m^2-16=0

a = 54; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·54·(-16)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{6}}{2*54}=\frac{0-24\sqrt{6}}{108}
=-\frac{24\sqrt{6}}{108}
=-\frac{2\sqrt{6}}{9}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{6}}{2*54}=\frac{0+24\sqrt{6}}{108}
=\frac{24\sqrt{6}}{108}
=\frac{2\sqrt{6}}{9}
$